Integrand size = 22, antiderivative size = 181 \[ \int (c+d x)^2 \cos ^2(a+b x) \cot (a+b x) \, dx=\frac {c d x}{2 b}+\frac {d^2 x^2}{4 b}-\frac {i (c+d x)^3}{3 d}+\frac {(c+d x)^2 \log \left (1-e^{2 i (a+b x)}\right )}{b}-\frac {i d (c+d x) \operatorname {PolyLog}\left (2,e^{2 i (a+b x)}\right )}{b^2}+\frac {d^2 \operatorname {PolyLog}\left (3,e^{2 i (a+b x)}\right )}{2 b^3}-\frac {d (c+d x) \cos (a+b x) \sin (a+b x)}{2 b^2}+\frac {d^2 \sin ^2(a+b x)}{4 b^3}-\frac {(c+d x)^2 \sin ^2(a+b x)}{2 b} \]
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Time = 0.27 (sec) , antiderivative size = 181, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.364, Rules used = {4493, 4489, 3391, 3798, 2221, 2611, 2320, 6724} \[ \int (c+d x)^2 \cos ^2(a+b x) \cot (a+b x) \, dx=\frac {d^2 \operatorname {PolyLog}\left (3,e^{2 i (a+b x)}\right )}{2 b^3}+\frac {d^2 \sin ^2(a+b x)}{4 b^3}-\frac {i d (c+d x) \operatorname {PolyLog}\left (2,e^{2 i (a+b x)}\right )}{b^2}-\frac {d (c+d x) \sin (a+b x) \cos (a+b x)}{2 b^2}+\frac {(c+d x)^2 \log \left (1-e^{2 i (a+b x)}\right )}{b}-\frac {(c+d x)^2 \sin ^2(a+b x)}{2 b}+\frac {c d x}{2 b}+\frac {d^2 x^2}{4 b}-\frac {i (c+d x)^3}{3 d} \]
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Rule 2221
Rule 2320
Rule 2611
Rule 3391
Rule 3798
Rule 4489
Rule 4493
Rule 6724
Rubi steps \begin{align*} \text {integral}& = \int (c+d x)^2 \cot (a+b x) \, dx-\int (c+d x)^2 \cos (a+b x) \sin (a+b x) \, dx \\ & = -\frac {i (c+d x)^3}{3 d}-\frac {(c+d x)^2 \sin ^2(a+b x)}{2 b}-2 i \int \frac {e^{2 i (a+b x)} (c+d x)^2}{1-e^{2 i (a+b x)}} \, dx+\frac {d \int (c+d x) \sin ^2(a+b x) \, dx}{b} \\ & = -\frac {i (c+d x)^3}{3 d}+\frac {(c+d x)^2 \log \left (1-e^{2 i (a+b x)}\right )}{b}-\frac {d (c+d x) \cos (a+b x) \sin (a+b x)}{2 b^2}+\frac {d^2 \sin ^2(a+b x)}{4 b^3}-\frac {(c+d x)^2 \sin ^2(a+b x)}{2 b}+\frac {d \int (c+d x) \, dx}{2 b}-\frac {(2 d) \int (c+d x) \log \left (1-e^{2 i (a+b x)}\right ) \, dx}{b} \\ & = \frac {c d x}{2 b}+\frac {d^2 x^2}{4 b}-\frac {i (c+d x)^3}{3 d}+\frac {(c+d x)^2 \log \left (1-e^{2 i (a+b x)}\right )}{b}-\frac {i d (c+d x) \operatorname {PolyLog}\left (2,e^{2 i (a+b x)}\right )}{b^2}-\frac {d (c+d x) \cos (a+b x) \sin (a+b x)}{2 b^2}+\frac {d^2 \sin ^2(a+b x)}{4 b^3}-\frac {(c+d x)^2 \sin ^2(a+b x)}{2 b}+\frac {\left (i d^2\right ) \int \operatorname {PolyLog}\left (2,e^{2 i (a+b x)}\right ) \, dx}{b^2} \\ & = \frac {c d x}{2 b}+\frac {d^2 x^2}{4 b}-\frac {i (c+d x)^3}{3 d}+\frac {(c+d x)^2 \log \left (1-e^{2 i (a+b x)}\right )}{b}-\frac {i d (c+d x) \operatorname {PolyLog}\left (2,e^{2 i (a+b x)}\right )}{b^2}-\frac {d (c+d x) \cos (a+b x) \sin (a+b x)}{2 b^2}+\frac {d^2 \sin ^2(a+b x)}{4 b^3}-\frac {(c+d x)^2 \sin ^2(a+b x)}{2 b}+\frac {d^2 \text {Subst}\left (\int \frac {\operatorname {PolyLog}(2,x)}{x} \, dx,x,e^{2 i (a+b x)}\right )}{2 b^3} \\ & = \frac {c d x}{2 b}+\frac {d^2 x^2}{4 b}-\frac {i (c+d x)^3}{3 d}+\frac {(c+d x)^2 \log \left (1-e^{2 i (a+b x)}\right )}{b}-\frac {i d (c+d x) \operatorname {PolyLog}\left (2,e^{2 i (a+b x)}\right )}{b^2}+\frac {d^2 \operatorname {PolyLog}\left (3,e^{2 i (a+b x)}\right )}{2 b^3}-\frac {d (c+d x) \cos (a+b x) \sin (a+b x)}{2 b^2}+\frac {d^2 \sin ^2(a+b x)}{4 b^3}-\frac {(c+d x)^2 \sin ^2(a+b x)}{2 b} \\ \end{align*}
Both result and optimal contain complex but leaf count is larger than twice the leaf count of optimal. \(564\) vs. \(2(181)=362\).
Time = 3.18 (sec) , antiderivative size = 564, normalized size of antiderivative = 3.12 \[ \int (c+d x)^2 \cos ^2(a+b x) \cot (a+b x) \, dx=\frac {48 i b^2 c d \pi x+16 i b^3 d^2 x^3-96 i b^2 c d x \arctan (\tan (a))+48 b^3 c d x^2 \cot (a)-6 b c d \cos (a+2 b x) \csc (a)-6 b d^2 x \cos (a+2 b x) \csc (a)+6 b c d \cos (3 a+2 b x) \csc (a)+6 b d^2 x \cos (3 a+2 b x) \csc (a)+48 b c d \pi \log \left (1+e^{-2 i b x}\right )+48 b^2 d^2 x^2 \log \left (1-e^{-i (a+b x)}\right )+48 b^2 d^2 x^2 \log \left (1+e^{-i (a+b x)}\right )+96 b^2 c d x \log \left (1-e^{2 i (b x+\arctan (\tan (a)))}\right )+96 b c d \arctan (\tan (a)) \log \left (1-e^{2 i (b x+\arctan (\tan (a)))}\right )-48 b c d \pi \log (\cos (b x))+48 b^2 c^2 \log (\sin (a+b x))-96 b c d \arctan (\tan (a)) \log (\sin (b x+\arctan (\tan (a))))+96 i b d^2 x \operatorname {PolyLog}\left (2,-e^{-i (a+b x)}\right )+96 i b d^2 x \operatorname {PolyLog}\left (2,e^{-i (a+b x)}\right )-48 i b c d \operatorname {PolyLog}\left (2,e^{2 i (b x+\arctan (\tan (a)))}\right )+96 d^2 \operatorname {PolyLog}\left (3,-e^{-i (a+b x)}\right )+96 d^2 \operatorname {PolyLog}\left (3,e^{-i (a+b x)}\right )-48 b^3 c d e^{i \arctan (\tan (a))} x^2 \cot (a) \sqrt {\sec ^2(a)}-6 b^2 c^2 \csc (a) \sin (a+2 b x)+3 d^2 \csc (a) \sin (a+2 b x)-12 b^2 c d x \csc (a) \sin (a+2 b x)-6 b^2 d^2 x^2 \csc (a) \sin (a+2 b x)+6 b^2 c^2 \csc (a) \sin (3 a+2 b x)-3 d^2 \csc (a) \sin (3 a+2 b x)+12 b^2 c d x \csc (a) \sin (3 a+2 b x)+6 b^2 d^2 x^2 \csc (a) \sin (3 a+2 b x)}{48 b^3} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 543 vs. \(2 (159 ) = 318\).
Time = 1.87 (sec) , antiderivative size = 544, normalized size of antiderivative = 3.01
method | result | size |
risch | \(-\frac {d \left (d x +c \right ) \sin \left (2 x b +2 a \right )}{4 b^{2}}+\frac {\left (2 x^{2} d^{2} b^{2}+4 b^{2} c d x +2 b^{2} c^{2}-d^{2}\right ) \cos \left (2 x b +2 a \right )}{8 b^{3}}-\frac {4 i d c x a}{b}-\frac {2 i d^{2} \operatorname {polylog}\left (2, {\mathrm e}^{i \left (x b +a \right )}\right ) x}{b^{2}}-\frac {2 i d^{2} \operatorname {polylog}\left (2, -{\mathrm e}^{i \left (x b +a \right )}\right ) x}{b^{2}}+\frac {2 d c \ln \left ({\mathrm e}^{i \left (x b +a \right )}+1\right ) x}{b}+\frac {2 d c \ln \left (1-{\mathrm e}^{i \left (x b +a \right )}\right ) a}{b^{2}}+\frac {4 c d a \ln \left ({\mathrm e}^{i \left (x b +a \right )}\right )}{b^{2}}-\frac {2 c d a \ln \left ({\mathrm e}^{i \left (x b +a \right )}-1\right )}{b^{2}}+\frac {2 d c \ln \left (1-{\mathrm e}^{i \left (x b +a \right )}\right ) x}{b}-\frac {2 i d c \,a^{2}}{b^{2}}-\frac {2 i d c \operatorname {polylog}\left (2, {\mathrm e}^{i \left (x b +a \right )}\right )}{b^{2}}-\frac {2 i d c \operatorname {polylog}\left (2, -{\mathrm e}^{i \left (x b +a \right )}\right )}{b^{2}}+\frac {2 i d^{2} a^{2} x}{b^{2}}+\frac {c^{2} \ln \left ({\mathrm e}^{i \left (x b +a \right )}+1\right )}{b}-\frac {2 c^{2} \ln \left ({\mathrm e}^{i \left (x b +a \right )}\right )}{b}+\frac {c^{2} \ln \left ({\mathrm e}^{i \left (x b +a \right )}-1\right )}{b}+i c^{2} x +\frac {i c^{3}}{3 d}-\frac {i d^{2} x^{3}}{3}+\frac {2 d^{2} \operatorname {polylog}\left (3, -{\mathrm e}^{i \left (x b +a \right )}\right )}{b^{3}}+\frac {2 d^{2} \operatorname {polylog}\left (3, {\mathrm e}^{i \left (x b +a \right )}\right )}{b^{3}}-i d c \,x^{2}-\frac {d^{2} \ln \left (1-{\mathrm e}^{i \left (x b +a \right )}\right ) a^{2}}{b^{3}}+\frac {d^{2} \ln \left (1-{\mathrm e}^{i \left (x b +a \right )}\right ) x^{2}}{b}+\frac {d^{2} \ln \left ({\mathrm e}^{i \left (x b +a \right )}+1\right ) x^{2}}{b}-\frac {2 d^{2} a^{2} \ln \left ({\mathrm e}^{i \left (x b +a \right )}\right )}{b^{3}}+\frac {d^{2} a^{2} \ln \left ({\mathrm e}^{i \left (x b +a \right )}-1\right )}{b^{3}}+\frac {4 i d^{2} a^{3}}{3 b^{3}}\) | \(544\) |
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 594 vs. \(2 (156) = 312\).
Time = 0.29 (sec) , antiderivative size = 594, normalized size of antiderivative = 3.28 \[ \int (c+d x)^2 \cos ^2(a+b x) \cot (a+b x) \, dx=-\frac {b^{2} d^{2} x^{2} + 2 \, b^{2} c d x - {\left (2 \, b^{2} d^{2} x^{2} + 4 \, b^{2} c d x + 2 \, b^{2} c^{2} - d^{2}\right )} \cos \left (b x + a\right )^{2} - 4 \, d^{2} {\rm polylog}\left (3, \cos \left (b x + a\right ) + i \, \sin \left (b x + a\right )\right ) - 4 \, d^{2} {\rm polylog}\left (3, \cos \left (b x + a\right ) - i \, \sin \left (b x + a\right )\right ) - 4 \, d^{2} {\rm polylog}\left (3, -\cos \left (b x + a\right ) + i \, \sin \left (b x + a\right )\right ) - 4 \, d^{2} {\rm polylog}\left (3, -\cos \left (b x + a\right ) - i \, \sin \left (b x + a\right )\right ) + 2 \, {\left (b d^{2} x + b c d\right )} \cos \left (b x + a\right ) \sin \left (b x + a\right ) + 4 \, {\left (i \, b d^{2} x + i \, b c d\right )} {\rm Li}_2\left (\cos \left (b x + a\right ) + i \, \sin \left (b x + a\right )\right ) + 4 \, {\left (-i \, b d^{2} x - i \, b c d\right )} {\rm Li}_2\left (\cos \left (b x + a\right ) - i \, \sin \left (b x + a\right )\right ) + 4 \, {\left (-i \, b d^{2} x - i \, b c d\right )} {\rm Li}_2\left (-\cos \left (b x + a\right ) + i \, \sin \left (b x + a\right )\right ) + 4 \, {\left (i \, b d^{2} x + i \, b c d\right )} {\rm Li}_2\left (-\cos \left (b x + a\right ) - i \, \sin \left (b x + a\right )\right ) - 2 \, {\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x + b^{2} c^{2}\right )} \log \left (\cos \left (b x + a\right ) + i \, \sin \left (b x + a\right ) + 1\right ) - 2 \, {\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x + b^{2} c^{2}\right )} \log \left (\cos \left (b x + a\right ) - i \, \sin \left (b x + a\right ) + 1\right ) - 2 \, {\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )} \log \left (-\frac {1}{2} \, \cos \left (b x + a\right ) + \frac {1}{2} i \, \sin \left (b x + a\right ) + \frac {1}{2}\right ) - 2 \, {\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )} \log \left (-\frac {1}{2} \, \cos \left (b x + a\right ) - \frac {1}{2} i \, \sin \left (b x + a\right ) + \frac {1}{2}\right ) - 2 \, {\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x + 2 \, a b c d - a^{2} d^{2}\right )} \log \left (-\cos \left (b x + a\right ) + i \, \sin \left (b x + a\right ) + 1\right ) - 2 \, {\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x + 2 \, a b c d - a^{2} d^{2}\right )} \log \left (-\cos \left (b x + a\right ) - i \, \sin \left (b x + a\right ) + 1\right )}{4 \, b^{3}} \]
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\[ \int (c+d x)^2 \cos ^2(a+b x) \cot (a+b x) \, dx=\int \left (c + d x\right )^{2} \cos ^{2}{\left (a + b x \right )} \cot {\left (a + b x \right )}\, dx \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 529 vs. \(2 (156) = 312\).
Time = 0.36 (sec) , antiderivative size = 529, normalized size of antiderivative = 2.92 \[ \int (c+d x)^2 \cos ^2(a+b x) \cot (a+b x) \, dx=-\frac {12 \, {\left (\sin \left (b x + a\right )^{2} - \log \left (\sin \left (b x + a\right )^{2}\right )\right )} c^{2} - \frac {24 \, {\left (\sin \left (b x + a\right )^{2} - \log \left (\sin \left (b x + a\right )^{2}\right )\right )} a c d}{b} + \frac {12 \, {\left (\sin \left (b x + a\right )^{2} - \log \left (\sin \left (b x + a\right )^{2}\right )\right )} a^{2} d^{2}}{b^{2}} - \frac {-8 i \, {\left (b x + a\right )}^{3} d^{2} - 24 \, {\left (i \, b c d - i \, a d^{2}\right )} {\left (b x + a\right )}^{2} + 48 \, d^{2} {\rm Li}_{3}(-e^{\left (i \, b x + i \, a\right )}) + 48 \, d^{2} {\rm Li}_{3}(e^{\left (i \, b x + i \, a\right )}) - 24 \, {\left (-i \, {\left (b x + a\right )}^{2} d^{2} + 2 \, {\left (-i \, b c d + i \, a d^{2}\right )} {\left (b x + a\right )}\right )} \arctan \left (\sin \left (b x + a\right ), \cos \left (b x + a\right ) + 1\right ) - 24 \, {\left (i \, {\left (b x + a\right )}^{2} d^{2} + 2 \, {\left (i \, b c d - i \, a d^{2}\right )} {\left (b x + a\right )}\right )} \arctan \left (\sin \left (b x + a\right ), -\cos \left (b x + a\right ) + 1\right ) + 3 \, {\left (2 \, {\left (b x + a\right )}^{2} d^{2} + 4 \, {\left (b c d - a d^{2}\right )} {\left (b x + a\right )} - d^{2}\right )} \cos \left (2 \, b x + 2 \, a\right ) - 48 \, {\left (i \, b c d + i \, {\left (b x + a\right )} d^{2} - i \, a d^{2}\right )} {\rm Li}_2\left (-e^{\left (i \, b x + i \, a\right )}\right ) - 48 \, {\left (i \, b c d + i \, {\left (b x + a\right )} d^{2} - i \, a d^{2}\right )} {\rm Li}_2\left (e^{\left (i \, b x + i \, a\right )}\right ) + 12 \, {\left ({\left (b x + a\right )}^{2} d^{2} + 2 \, {\left (b c d - a d^{2}\right )} {\left (b x + a\right )}\right )} \log \left (\cos \left (b x + a\right )^{2} + \sin \left (b x + a\right )^{2} + 2 \, \cos \left (b x + a\right ) + 1\right ) + 12 \, {\left ({\left (b x + a\right )}^{2} d^{2} + 2 \, {\left (b c d - a d^{2}\right )} {\left (b x + a\right )}\right )} \log \left (\cos \left (b x + a\right )^{2} + \sin \left (b x + a\right )^{2} - 2 \, \cos \left (b x + a\right ) + 1\right ) - 6 \, {\left (b c d + {\left (b x + a\right )} d^{2} - a d^{2}\right )} \sin \left (2 \, b x + 2 \, a\right )}{b^{2}}}{24 \, b} \]
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\[ \int (c+d x)^2 \cos ^2(a+b x) \cot (a+b x) \, dx=\int { {\left (d x + c\right )}^{2} \cos \left (b x + a\right )^{2} \cot \left (b x + a\right ) \,d x } \]
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Timed out. \[ \int (c+d x)^2 \cos ^2(a+b x) \cot (a+b x) \, dx=\int {\cos \left (a+b\,x\right )}^2\,\mathrm {cot}\left (a+b\,x\right )\,{\left (c+d\,x\right )}^2 \,d x \]
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